The equation h(t)=−16t2+25t+80 gives the height of a ball, in feet, t seconds after it is thrown from a platform.
what is the initial velocity when the ball is thrown?

initial velocity when the ball is thrown is 25 ft/sec.

Step-by-step explanation:

The height of the object of the projectile motion is given by:

          ....[1]

where

a is the acceleration due to gravity i.,e a = 16 ft/s^2

is the initial velocity

is the initial height of the object.

Given the equation:

where

h(t) is the height of the ball in feet after it is thrown from a platform.

t is the time in seconds

On comparing the given equations with [1] we have;

⇒ ft/sec

therefore, the initial velocity when the ball is thrown is 25 ft/sec.

whats the

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)