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Mathematics, 16.10.2019 04:00 jpyperofficialp2z5xs

In square $abcd$, $e$ is the midpoint of $\overline{bc}$, and $f$ is the midpoint of $\overline{cd}$. let $g$ be the intersection of $\overline{ae}$ and $\overline{bf}$. prove that $dg = ab$.

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In square $abcd$, $e$ is the midpoint of $\overline{bc}$, and $f$ is the midpoint of $\overline{cd}$...
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