Atriangular sail has a base length of 2.5 m the area of the sail is 3.75 m² how tall is the sail

The answer is:  " 3 m " .   The sail is:  " 3 meters tall". 


Area of triangle, "A", equals "(1/2)" * (base) * (height) :

  A = (1/2) * b * h ; 

Given:  "A = 3.75 m² " ;  AND:
             "b = 2.5 m " ;  

Solve for "h"  ;

Given:  A =  (1/2) * b * h ; 

Rearrange the equation to isolate "h" on one side of the equation;
       Then, plug in the "known values" to solve for, "h" ;

Given:  A = (1/2) * b * h ;

Rewrite as:

            A = (b*h) / 2 ;

Now, multiply EACH side of the equation by "2" ; 

                 2 *A = { (b*h) / 2 } * 2 ;

  To get:   2A = b * h ; 

Now, divide EACH side of the equation by "b", to isolate "h" on one side             of the equation (and ultimately, solve for "h") ;

               2A / b = (b * h) / b ; 

  to get:   2A / b = h ;  ↔  h = 2A / b ;

Now, we have:   h = 2A / b ; plug in the values given for "A" and for "b" ; 
        to solve for "h" ; 

    h = [ 2*(3.75 m²) ] / 2.5 m = 7.5 m² / 2.5 m = 3 m.

The answer is:  3 m .   The height is:  3 m .