Mathematics, 19.10.2019 14:00 katietinary1657

Its almost midnight and im taking my benchmarks

girls boys
10 8
12 6
9 4
15 5
25 10
8 15
6 7
14 8
18 12
11 11
9 9
13 5
15 4

jeffrey surveys the 13 girls and 13 boys in his class to find out how many pairs of shoes they have in their closets. which statement is true?
a) the value of q3 for the boys is greater than the value of q3 for the girls.
b) the mean number of shoes for the boys is greater than the mean number of shoes for the girls.
c) the median number of shoes for the girls is greater than the median number of shoes for the boys.
d) the median number of shoes for the boys is greater than the median number of shoes for the girls.

Answers: 2

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Answer from: hayden6920

The median number of shoes for the girls is greater than the median number of shoes for the boys.

Step-by-step explanation:

Jeffrey surveys the 13 girls and 13 boys in his class to find out how many pairs of shoes they have in their closets

Girls Data :10, 12, 9 , 15, 25,8, 6,14, 18 , 11 , 9 , 13 , 15

Arrange the data in the ascending order :

6,8,9,9,10,11,12,13,14,15,15,18,25

No. of observations n = 13(odd)

So, Median = $(\frac{n+1}{2})^{\text{th term}}$

= $(\frac{13+1}{2})^{\text{th term}}$

= $(\frac{14}{2})^{\text{th term}}$

= $(7)^{\text{th term}}$

Thus the median of the girls data is 12.

Now to find Q_3

Consider the set of values right to the median .

13,14,15,15,18,25

Now find the median of this data

No. of observations n = 6(even)

Median = $\frac{(\frac{n}{2}+1)^{\text{th term}}+\frac{n}{2}^{\text{th term}}}{2}$

So, Median = $\frac{(\frac{6}{2}+1)^{\text{th term}}+\frac{6}{2}^{\text{th term}}}{2}$

Median = $\frac{4^{\text{th term}}+3^{\text{rd term}}}{2}$

Median = $\frac{15+15}{2}$

Median =

Mean = $\frac{\text{Sum of all observations }}{\text{number of observations}}$

Mean = $\frac{10+12+ 9 +15+25+8+6+14+18+ 11 +9+ 13+15}{13}$

Mean = 12.69

So, Q_3 for girls is 15 and median is 12 and mean is 12.6.

Boys data : 8,6,4,5,10,15,7,8,12,11,9,5,4

Arrange the data in the ascending order :

4,4,5,5,6,7,8,8,9,10,11,12,15

No. of observations n = 13(odd)

So, Median = $(\frac{n+1}{2})^{\text{th term}}$

= $(\frac{13+1}{2})^{\text{th term}}$

= $(\frac{14}{2})^{\text{th term}}$

= $(7)^{\text{th term}}$

Thus the median of the boys data is 8

Now to find Q_3

Consider the set of values right to the median .

8,9,10,11,12,15

Now find the median of this data

No. of observations n = 6(even)

Median = $\frac{(\frac{n}{2}+1)^{\text{th term}}+\frac{n}{2}^{\text{th term}}}{2}$

So, Median = $\frac{(\frac{6}{2}+1)^{\text{th term}}+\frac{6}{2}^{\text{th term}}}{2}$

Median = $\frac{4^{\text{th term}}+3^{\text{rd term}}}{2}$

Median = $\frac{11+10}{2}$

Median = 10.5

Mean = $\frac{\text{Sum of all observations }}{\text{number of observations}}$

Mean = $\frac{4+4+5+5+6+7+8+8+9+10+11+12+15}{13}$

Mean =

So, Q_3 for boys is 10.3 and median is 8 and mean is 8

Since we can see that the value of Q_3 , mean and median opf girls is greater than boys.

So, Option C is correct.

The median number of shoes for the girls is greater than the median number of shoes for the boys.

Answer from: Quest

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

Afive question multiple-choice quiz has five choices for each answer. use the random number table pr

Answer from: Quest

40%=2/550=1/230=3/1056=14/25

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Its almost midnight and im taking my benchmarks

girls boys
10 8
12 6
...

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