Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. how many pounds of the more expensive candy are needed to produce a 15-pound mixture that sells for $7.00 per pound?

5
6
9
10

5 Pounds

Step-by-step explanation:

Let A represent the number of pounds of $6 candy

Let B represent the number of pounds of $9 candy

Therefore ,

A + B = 15

A= 15 - B

6 × A + 9 × B = 15 × 7

6A + 9B = 105

In order to find B we substitute 15-B for A in the equation.

6 x (15 - B ) + 9B = 105

90 - 6B + 9B = 105

3B = 105 - 90

3B = 15

B = 5

To solve for A

A = 15 - B

Where B is 5

A = 15 - 5

A = 10

From the calculation,

Number of pounds of $6 per pound candy is 10 and the number of pounds of the $9 per pound candy is 5.

Therefore, since B is representing the number of pounds of the $9 candy , and it is the most expensive, then 5 pounds of the more expensive candy are needed to produce a 15-pound mixture that sells for $7.00 per pound.

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step-by-step explanation:

∈3,600

step-by-step explanation: