Me just wait for me to put the pictures up but this time wait

1.A.
The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm.
1.B.
The formula for the area of a trapezoid is
A=(b1+b2)/2*h
plug in the data we know
A=(35+19)/2*15
A=54/2*15
A=27*15
A=405cm²
since there are two trapezoids, we double that number  405*2=810cm²
Answer=810cm²

1.C.
To solve for this, we need to find the perimeter of the trapezoid
P=35+19+17+17=88cm
Answer=No. The edges of the trapezoid are longer than 80cm.

2.A.
3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3
Answer=3

2.B
A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench

3.A
The two triangles would be...
A=1/2b*h=1/2*30*72=15*72=1080ft² each
and the center rectangle would be
A=l*w=20*72=1440ft²
Add them all together and you get
Total area=3600ft²

Ibelieve the answer is c i worked it out three times but if my answer is wrong someone correct me