How to find the standard form of an ellipse?

 general format of an ellipse is ax2 + by2 + cx + dy + e = 0. But the more useful form looks quite different:

(x-h)^2 over a^2 plus (y-k)^2 over b^2=1                where the point (h,k) is the center of the ellipse

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

are you an artist's daughter? cuz dang you a fine piece of art, girl.