Idon't understand how to solve this equation.

X^2+10x-4=0  

There are a couple of ways to solve this, you can complete the square or use the quadratic formula (which is derived from the steps to completing the square).  Factoring in this case would be very difficult as there are no easy integer values to solve it with.  So we'll complete the square:

Move the constant to the other side by adding 4 to both sides...

x^2+10x=4  Now halve the linear coefficient, 10 in this case, square that value and add it to both sides...ie 10/2=5, 5^2=25, so add 25 to both sides

x^2+10x+25=29  Now the left side is a perfect square

(x+5)^2=29  now take the square root of both sides...

x+5=±√29  finally subtract 5 from both sides...

x=-5±√29

So x=-5+√29 and -5-√29

The first option would be correct if it were one half and not one