Abird starts from the ground, flies at a certain speed for 5 seconds, and lands on a tree branch. the vector representing its position is . it continues to fly in the same direction and at the same speed for 5 more seconds, and lands on another branch. what vector represents its new position from the ground?

Answer with explanation:

Let the Speed at which bird is flying = u m/s

⇒Distance = Speed × Time

So,After 5 Seconds , position of Bird = 5 u meter

After,10 Seconds , position of Bird = 10 u meter

If ground is considered as two dimensional plane,and time is represented on X axis(i plane) and Distance on Y axis(j plane),,then

Position of bird after 5 seconds= (5, 5 u)=5 i + 5 u jFirst Branch

Position of bird after 10 seconds= (10, 10 u)=10  i+10 u jSecond Branch(New Position)

Change in position of bird =Final Position - Initial Position

                      =1 0  i + 10 u j - 5 i -5 u j  

                     = 5 i +5 u  j

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92