Idon't know to get the interval notation

(x^2+3)/(4x)≥1  multiply both sides by 4x

x^2+3≥4x  subtract 4x from both sides...

x^2-4x+3≥0  factor left side...

(x-1)(x-3)≥0  for this to be true both terms need to be positive or both terms need to be negative or either one of them are equal to zero. 

x≥3 and x≤1 thus the interval is

x=(-oo, 1], [3, +oo)

11/36 is .305 repeating