The list below shows all of the possible outcomes for flipping four coins. hhht hhth hhtt hthh htht htth httt thhh thht thth thtt tthh ttht ttth what is the probability of at least two coins landing on heads?

Step-by-step explanation:

We have total of 16 possible outcomes for flipping of four coins

We need to find the probability when atleast two head comes that means it should be atleast 2 head means it can be more than 2 so, can be 3 or 4 also

We will consider the cases of  2,3,4 heads on coins

So, the cases of 2 heads are HHTT ,HTHT ,HTTH, THHT ,THTH ,TTHH =6 outcomes

The case of 3 heads are HHHT ,HHTH ,HTHH, THHH=4 outcomes

The case of 4 heads are HHHH=1 outcome

So, the probability of atleast two head will be 6+4+1=11

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

yes

step-by-step explanation:

yes