Aregular heptagon has sides measuring 26 mm and is divided into seven congruent triangles each triangle has a height of 27 mm what is the area of the heptagon

36x2 + 49y2 = 1,764 the foci are located at: (-√13, 0) and (√13,0) (0, -√13) and (0,√13) (-1, 0) and (1, 0)edit: the answer is (- the square root of 13, 0) and (the square root of 13, 0)