Consider a political discussion group consisting of 10 democrats, 7 republicans, and 6 independents. suppose that two group members are randomly selected, in succession, to attend convention. find the probability of selecting two republicans

Let's firstly consider the number of ways in which you can pick two people from 23 people: 23C2

Now, how many ways can we choose 2 Republicans? Well, we have 7 Republicans and we want to choose 2 of them: 7C2

Therefore, P(2 Republicans) =

Correct me if I'm wrong, haven't done permutations and combinations in a while.

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.

31 is prime. and it’s prime factorization is just 31.