This is confusing! ~! ~!

find the dimensions of the rectangle that has a length 3 meters more that its width and a perimeter equal in value to its area?

 L is the length and W is the width of the rectangle. L = W + 3 

The Perimeter = 2L + 2W = 2(W + 3) + 2W = 4W + 6 

The Area = L W = (W + 3) W = W2 + 3 W 

The Area and Perimeter are equal in value, so 

W2 + 3 W = 4W + 6 

Now the above quadratic equation for W and we substitute to find L btw 

W = 3 and L + 6

I hope this helped!

So,
Perimeter = 2L + 2W = 2(W + 3) + 2W = 4W + 6 

Area = L W = (W + 3) W = W2 + 3 W 

= W2 + 3 W = 4W + 6 

= W = 3 and L + 6

Hope this helps!