one x-intercept for a parabola is at a point (1,0). use the factor method to find the other x-intercept for the parabola defined by this equation:
y=2x^2+2x-4
separate by a comma

let's verify that (1,0) is indeed an x-intercept of the parabola y=2x^2+2x-4. replace each instance of x with 1: y=2*(1)^2 + 2(1) - 4 = 0. yes, it is.

if (1,0) is an x-intercept, it's also a root, and so (x-1) is a factor. dividing y=2x^2+2x-4 by (x-1) results in a quotient of 2x+4, or 2(x+2), which, if set = to zero, yields x = -2 as the other root or x-intercept.

it is probably the graph on the bottom right.