Which rotation about its center will carry a regular decagon onto itself

The answer is any multiple of 36.

Step-by-step explanation:

A decagon has 10 sides, and it has 10 exterior angles of 36° as can be seen in the picture.

Therefore, by rotating the decagon about its center by multiples of 36° will carry a regular decagon onto itself.

Any multiple of 36 could be: 36, 72, 108, 144, 180, 216, 252, 288, etc...

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.