Solve the system of equations algebraically. show all of your steps
y=x^2+2x
y=3x+20

can you , really

I am going to explain this using the substitution method, considering it appears to be the best in this situation.

We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:

3x+20=x^2+2x

Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you

x+20=x^2

Now, we take the square root of both sides to get

rad(x+20)=x

Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes

2rad(x+5)

This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...