Mathematics, 26.09.2019 13:30 roblesjairus
At what point on the curve y=x+2cos x is the tangent horizontal in the interval [-2pi, 2pi]
Answers: 1
![\bf y=x+2cos(x)\qquad \qquad [-2\pi ,2\pi ]\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=1-2sin(x)\implies 0=1-2sin(x)\implies sin(x)=\cfrac{1}{2} \\\\\\ \measuredangle x=sin^{-1}\left( \frac{1}{2} \right)\implies \measuredangle x= \begin{cases} \frac{\pi }{6}\\\\ \frac{5\pi }{6} \end{cases}](/tpl/images/0264/7904/e0ab2.png)
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At what point on the curve y=x+2cos x is the tangent horizontal in the interval [-2pi, 2pi]...
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