Mathematics, 19.08.2019 17:50 johngayden46

Plotting at least 3 points y=2/3x-5

Answers: 2

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First you must plot one point on the y-axis. This point will be -5 because the y-intercept is a -5. Then you look at the slope. This is the number in front of the x. The numerator tells you how far up or down to go and the denominator tells you how far left or right to go. Because the slope is positive, we will go 2 points up from -5, and 3 points right from that. Plot your point. Then do the same thing from there. 2 up and 3 right and so on.

Answer from: reyescoralys

Y = 2/3x - 5
y + 5 = 2/3x - 5 + 5
3/2(y + 5) = 2/3x · 3/2
3/2y + 7 1/2 = x
y = 2/3(3/2y + 7 1/2) - 5
y = y + 5 - 5
y = y + 0
-y -y
0y = 0
0 0
y = 0
0 = 2/3x - 5
+5 +5
3/2 · 5 = 2/3x · 3/2
7 1/2 = x
(x, y) = (7 1/2, 0)

Answer from: Quest

so the perpendicular line goes through the given pointyou would get a perpendicular line at some random location

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

Answer from: Quest

statement #3: proof- ang is congruent to ang ecd : angles are congruent.

step-by-step explanation:

1: the missing angles in statement #3

a.) acb

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.

2: the missing word in reason #3

c.) vertical

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.

i hope that was and understanding.