Arectangle has one vertex at 0,4 the rectangle has at least one side with the length of 6 units. which vertices could represent the other three vertices of the rectangle. a. 0,-2 -2,-2 and -2,4 b.3,4 3,1 and 0,1 c.6,4 0,2 and 6,2 d,-6,4 0,5 and -6,5 e. 0,6 2,6 and 2,4

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

yes, i think so although i am not sure. this is a very strange question.