Suppose an investment of $6,200 doubles in value every 13 years. how much is the investment worth after 78 years?

$396,800

Step-by-step explanation:

Given: The initial investment = $6200

The constant ratio = 2

Time takes to double the amount (Time period )= 13

The number of time periods in 78 years =

The exponential growth equation is given by :-

, whre A is the initial amount , b is the constant ratio and x is the number of time periods .

Now, the investment worth after 78 years will be given by :-

Hence, The  investment worth after 78 years is $396,800.

d: 0.7(t + 4 + 2) = t .

step-by-step explanation: