In a trapezoid abcd with legs ab and cd , the diagonals intersect each other at point o. compare the areas of △abd and △acd

The area of △ABD and △ACD are equal.

Step-by-step explanation:

Triangles lying   on same base and between same parallels are equal in area .

In a trapezoid the opposite sides are parallel.The legs of the trapezoid are AB and CD.The triangles △ABD and △ACD are having the same base AD and are lying between the same parallel lines AB and CD,so they are w=equal in area.

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step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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