4) landon is standing in a hole that is 6.5 m deep. he throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. the path of the rock can be modeled by the equation y=-0.05x^2+4.5x-6.5, where x is the horizontal distance of the rock, in meters, from landon and y is the height, in meters, of the rock above the ground. how far horizontally from landon will the rock land? round your answer to the nearest hundredth of a meter. (1 point)

a. 82.03 m <
b. 6.50 m
c. 90.00 m
d. 88.53 m

The rock will land 88.53 horizontally far from Landon.

Step-by-step explanation:

The path of the rock can be modeled by the equation:  

Where x is the horizontal distance of the rock, in meters, from landon and y is the height, in meters, of the rock above the ground.

Now we are supposed to find How far horizontally from landon will the rock land

when the rock land so y becomes 0

So, substitute y =0 is the given equation.

Use quadratic formula :

Substitute a = -0.05

b = 4.5

c= -6.5

So,

Thus It will be 88.53m horizontal distance from Landon when it strikes the ground.

The rock will be 1.47m horizontal distance from Landon where it exits the hole.

Hence Option D is correct.

The rock will land 88.53 horizontally far from Landon.

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy

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