Jason rolls a fair number cube labeled 1 through 6, and then he flips a coin. what is the probability that he rolls a 3 and flips a head?

Probability is 1/12.

Step-by-step explanation:

Since Jason rolls a cube labeled 1 through 6. Then to get any number when he rolls the cube probability will be = 1/6 = One event/ Total number of events

so probability of rolling a 3 = 1/6

Now he flips a coin then probability of getting head will be = 1/2

Since these two events are totally different therefore getting both the events ( getting 3 on rolling cube and flipping for head) will be = P1 × P2

P = (1/6).(1/2) = 1/12

So the answer is P = 1/12.

i dont know men

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)