Find the altitude of an isosceles triangle with a vertex angle (that is, the non-base angle) of 70° and a base of 246. draw a diagram and find the length of the altitude

AD=175.66 units

Step-by-step explanation:

It is given that ABC is an isosceles triangle in which base is 246 and the non base angle is 70°.

Thus, applying the angle sum property in ΔABC, we get

∠A+∠B+∠C=180°

⇒70°+2∠B=180°

⇒∠B=55°

Thus, ∠B=∠C=55°.

Now, Draw AD perpendicular to BC such that BD=DC=123, then applying trigonometry in ΔADC, we have

⇒

⇒

⇒

Thus, the length of the altitude is 175.66.

i can answer this question sweetie!

step-by-step explanation:

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%