Mr. hauseman has 17 students in his class, three of whom are freshmen, and the rest are from other classes. he is going to draw two students randomly to be partners.
he calculates the probability of drawing a freshman and then a junior to be
9/136. how many juniors must be in the class?
a.3 b.6 c.7 d.8

6

Step-by-step explanation:

Total students = 17

No. of freshmen = 3

Let number of juniors be x.

Since we are given that two students are drawn randomly .

He calculates the probability of drawing a freshman and then a junior to be

So, probability of getting freshman on first draw =

Since 1 student is already drawn .So, total no. of students = 16

So, probability of getting Junior on second draw =

So, probability of getting freshman and junior =

Since we are given that  the probability of drawing a freshman and then a junior to be  

So,

Hence there must be 6 juniors in the class.

d

step-by-step explanation:

d

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.