What is the sum? x/x+3 + 3/x+3 + 2/x+3
a) 5/3
b) x+5/x+3
c) x+5/3x+27
d) 6x/x+3

B

Step-by-step explanation:

x/(x+3) + 3/(x+3) + 2/(x+3)

The denominator is the same for all, so you can simply add them all respectively...

(x+3+2)/(x+3)

Now combine the like terms...

(x+5)/(x+3)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: