Starting at home, michael traveled uphill to the gift store for 24 minutes at just 10 mph. he then traveled back home along the same path downhill at a speed of 30 mph. what is his average speed for the entire trip from home to the gift store and back?

We can figure out how long Michael's trip took by realizing that 30 mph is 3 times 10 mph.  Because of this, the trip home will take 1/3 the amount of time it took to go up the hill.  This makes the equation 24 + 8 = 32 minutes for the whole trip.

Now we need to figure out how long the trip was.  We can do this by multiplying 10 minutes by 24/60, which equals 4.  This means that Michael went 4 miles there, and 4 miles back.  So Michael went a total of 8 miles.

Now we know that Michael went 8 miles in 32 minutes.  Now, we multiply 8 by 60/32.  This gives us 15, so Michael went 15 miles per hour on average in the trip.

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

Set square i think so