Find six trig values if sec(x)=-3/2 and tan(x)> 0 i got cos(x)=-2/3 but that is all i could get

sin x=

Step-by-step explanation:

We are given that

, cos (x)=

tan x >0

We have to find sinx , csc (x), tan (x), cot (x).

We know that

Using the formula

Then, we get

We are given that tan x >0  and cos x(x) <0

It means angle  x lies in III quadrant.

In III quadrant , sin x and cos x  are both negative and tan x is positive.

Therefore , sin x=

answer: d. $20

step-by-step explanation:

just took the test

there is no grid

step-by-step explanation: