Ajet, in calm air conditions, travels with velocity vector (389, 389). the wind velocity (in mph) at the plane’s cruising altitude is given by (0, 50). how fast is the plane’s true speed?

a. 587 mph
b. 590 mph
c. 600 mph
d. 601 mph

After thorough researching, if a jet in calm air conditions travels with velocity vector (389, 389) and the wind velocity (in mph) at the plane’s cruising altitude is given by (0, 50), then the plane’s true speed is 600 mph. The correct answer to the following given statement above is with the letter C.

3x+9+4x+x=8x+9that's the answer for your question.