How does the volume of an oblique cylinder change if the radius is reduced to 2004-06-01-04-00_files/i044.jpg of its original size and the height is quadrupled?

How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size & the height is quadrupled?

Volume of an oblique cylinder = π * r² * h

radius is reduced to 2/9 of its original size = r * 2/9 = (2r/9)
height is quadrupled = h * 4 = 4h

Volume of an oblique cylinder = π * (2r/9)² * 4h

Assume: r  = 9 ; h = 10

V = π * 9² * 10 = 3.14 * 81 * 10 = 2,543.40

V = π * (2²) * (10*4) = 3.14 * 4 * 40 = 502.4

The new volume decrease and is almost equivalent to 20% of the original volume. 

Geometric pattern of 2 i’m guessing. not really sure about what you’re asking but i hope this !

Aand b are correctly balanced reactions. they have the same number of atoms in both sides of the reaction