The ratio of the numerator to the denominator of a fraction is 2 to 3. if both the numerator and the denominator are increased by 2, the fraction becomes 3/4. what is the original fraction? which of the following systems of equations can be used to solve the problem?
n + 4 = 3 and d + 5 = 4
3n - 2d = 0 and 4n + 2 = 3d + 2
3n = 2d and 4n + 8 = 3d + 6

3n = 2d and 4n + 8 = 3d + 6

Step-by-step explanation:

First we must solve this by cross multiplying:

3n = 2d3 (d + 2) = 4(n + 2) = > 3d + 6 = 4n + 8

then substitute d = 3/2n in the 2nd one:

9/2n - 4n = 2 = > 1/2 n = 2 = > n = 4

if n = 4

then d = 3/2*4 = 6.

So the original fraction was 4/6

Overall the answer is 3n = 2d and 4n + 8 = 3d + 6.

Please mark my answer the brainliest.

Have a nice day