Amembership committee of three is formed from four eligible members. let the eligible members be represented by a, b, c, and d. the possible outcomes include s = {abc, abd, acd, bcd}.
which statements about the situation are true? check all that apply.
a. there are four ways to choose the committee.
b there are three ways to form the committee if person d must be on it.
c if seven members are eligible next year, then there will be fewer combinations.
d if persons b and c must be on the committee, there are two ways to form the committee.
e if persons a and c must be on the committee, then there is only one way to form the committee.
which ones do i

Options A, B and D are correct.

Step-by-step explanation:

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

The true statements about this situation are :

A. There are four ways to choose the committee.  As we can see 'S' has 4 ways.

B. There are three ways to form the committee if person D must be on it.  We have three sets that have D.

D. If person B and C must be on the committee, there are two ways to form the committee. Yes, B and C are only in 2 sets.

C. If seven members are eligible next year, then there will be fewer combinations. This is wrong as there will be more combinations like 7C6 if 6 are to be chosen out of 7.

E If persons A and C must be on the committee, then there is only one way to form the committee. This is wrong as we have two sets that have A and C in it.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: