Mathematics, 19.10.2019 09:10 nonispn606
Find an n^th degree polynomial with real coefficients satisfying the given conditions. n=4: 2i and -8i are zeros; f(-1)=325 the expanded and simplified polynomial is f(x)=
i had posted a similar question before and followed the steps but i'm doing something wrong and i'm not sure what
Answers: 2
![\bf \begin{cases} x=2i\implies &x-2i=0\\ x=-2i\implies &x+2i=0\\ x=-8i\implies &x+8i=0\\ x=8i\implies &x-8i=0 \end{cases} \\\\\\ (x-2i)(x+2i)(x+8i)(x-8i)=0\implies [x^2-(2i)^2][x^2-(8i)^2]=0 \\\\\\ (x^2+4)(x^2+64)=0\implies x^4+68x^2+256=0](/tpl/images/0334/0252/5e2b6.png)
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Find an n^th degree polynomial with real coefficients satisfying the given conditions. n=4: 2i and...
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