What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56?

Step-by-step explanation:

Here we have the first term but must find the common ratio, r.

The nth term is a(n) = 8(r)^(n - 1).

To find r, substitute 9 for n in the above, obtaining 8(r)^(9-1), or

a(9) = 8(r)^8 = 56.

Solving for r^8, we get 56/8, or just 7.

Then r^8 = 7, and so r = 7^(1/8).

Thus, a(n) = 8(7)^(1/8)^(n-1), and so

a(24) = 8(7)^(23/8), or 2151.53

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function