Find the dimensions of a rectangle with area 2,197 m2 whose perimeter is as small as possible. (if both values are the same number, enter it into both blanks.

Area of a rectangle A = l×w = 2197
l - length
w-width
l×w = 2197
making l the subject
l =
The perimeter of rectangle
p = 2(l+w)
   = 2(w+)
   =2w+
To obtain minimal perimeter

2- = 0
multiplying both sides of equation by
2-4394=0
2=4394
=2197
w = √2197
   w1 = 46.87
   w2 = 46.87

The length of what is left would be 1 1/2 feet long.