What is the general form of the equation for the given circle centered at o(0, 0)?
a) x2 + y2 + 41 = 0
b) x2 + y2 − 41 = 0
c) x2 + y2 − 41 = 0
d) x2 + y2 + x − y − 41 = 0

 

hello :
an equation of the circle Center at the O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is :  x² +y² = 41

x² +y² - 41=0

Your answer would be ahere is how: perimeter is how long all the sides are. in a rectangle, there are two sets of parallel sides. so, to find this, we would to the following.(15x2)+(4x2)30+838if you have questions ask! and mark me brainliest! i really wanna level up : 3

If i'm correct the answer is $15.97