You have three $1 bills, four $5 bills, and two $10 bills in your pocket. you select a bill at random. without replacing a bill, you choose a second bill at random. find p($5 then $10)

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

the answer is b.)

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