From a ship, the angle of elevation of a point, a, at the top of a cliff is 21°. after the ship has sailed 2,500 feet directly toward the foot of the cliff, the angle of elevation of ∠a is 47°. (assume the cliff is perpendicular to the ground.) the height of the cliff is __ feet.

10701.97 feet.

Step-by-step explanation:

Refer the attached figure

The angle of elevation of a point, A, at the top of a cliff is 21° i.e. ∠ACB = 21°

The ship has sailed 2,500 feet directly toward the foot of the cliff i.e. CD = 2500 feet.

Then the angle of elevation becomes 47° i.e.∠ADB = 47°

Let BD be x

So, BC = BD+DC=x+2500

Let the height of the cliff be h feet.

In ΔABD

We will use trigonometric ratios

   ---a

In ΔABC

We will use trigonometric ratios

  -----b

Equate a and b

Thus the height of the cliff is 10701.97 feet.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

brandon has 4344 video games.  

step-by-step explanation

7373 - 2929 = 4344

pls let me know if it was correct