Apoint located at (6, -3) is translated down 6 units. what are the coordinates of the image?

(0, -3)
(6, -9)
(6, 3)
(12, -3)

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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