What is the line of symmetry for the parabola whose equation is y = x2 + 10x + 25?

x=−5

y=x2+10x+25

The line of symmetry passes through the vertex of the parabola. The x coordinate of the vertex is found with the formula x=−b2a for the equation of the form y=ax2+bx+c.

In this example, a=1, b=10 and c=25

x=−102⋅1=−5

Because the line of symmetry passes through the vertex, the equation of the line is x=−5.

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