How wide is a poster that has a length of
9/2
feet and area of
45/4
square feet?
a)
1/4 feet
b)
5/8 feet
c)
2/5 feet
d)
5/2 feet

The correct option is D.

Step-by-step explanation:

Given information:

Length of the poster = ft

Area of the poster = ft²

We need to find the width of the poster.

The area of a rectangular poster is

where, l is length and w is width.

Substitute and   in the above formula.

On cross multiplication we get

Divide both sides by 36.

Cancel out common factors.

The width of the poster is 5/2 ft.

Therefore the correct option is D.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.