Given that ∠xqr = 180° and ∠lqm = 180°, which equation could be used to solve problems involving the relationships between ∠mqr and ∠lqr?
a) (3a + 50) + 180 = (140 − 4a)
b) (3a + 50) + (140 − 4a) = 180
c) (140 − 4a) − 180 = (3a + 50)
d) (3a + 50) − (140 − 4a) = 180

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

answer: add the !

step-by-step explanation: then we will answer