Five pennies, 3 dimes, and 4 quarters are placed in a bag. what is the probability of selecting a penny and then a dime, given the first coin is not returned to the bag after it is drawn?

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.