Option B.
Step-by-step explanation:
The given equations of the system are
2x - y - 4 = 0
2x - 4 = y ------(1)
3x + y - 9 = 0
3x + y = 9
y = 9 - 3x ------(2)
By replacing the value of y from equation (1) to equation (2)
2x - 4 = 9 - 3x
2x = 4 + 9 - 3x
2x = 13 - 3x
2x + 3x = 13
5x = 13
x = ![\frac{13}{5}](/tpl/images/0383/7979/15de5.png)
Now we plug in the value of x in the equation (1)
![y=9-(3\times \frac{13}{5})](/tpl/images/0383/7979/e95e5.png)
![y=9-(\frac{39}{5})](/tpl/images/0383/7979/ed6a6.png)
![y=\frac{45-39}{5}](/tpl/images/0383/7979/45180.png)
![y=\frac{6}{5}](/tpl/images/0383/7979/6ff50.png)
Therefore, solution of the given system is
.
Option B. is the answer.