Compute the permutations and combinations. how many two-digit, positive integers can be formed from the digits 1, 3, 5, and 9, if no digit is repeated?

The number of two-digit, positive integers that can be formed from the digits 1, 3, 5, and 9, if no digit is repeated are:

                                12

We are asked to find the number of two-digit number that can be formed using the digits:

   1,3 ,5 and 9

We know that the number of such digits possible are:

    4×3=12

( Since at the first place there are 4 choices as any of the 4 numbers could come at the first place and also at the second place there are a choice of 3 numbers as the digit's can't be repeated )

       Hence, the answer is:

                    12

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: