Given a circle with measures of (c, d, and r) and a circle with measures of (c', d', and r'), what is r' if c c' = 3.0 and d = 12.0?

a) 2
b) 4
c) 8
d) 12

edit: the answer is a) 2

we know that

The circumference of a circle is equal to

where

D is the diameter of the circle

In this problem we have

the circumference of the circle is

------> equation A

the circumference of the circle is

------> equation B

and the ratio of the circumference of the circle to the circumference of the circle is

------> equation C

Substitute the equation A and equation B in the equation C

Find the radius r'

therefore

the answer is  the option A

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.