Write the equation of the line that is perpendicular to y = −14x + 2y = -14x + 2 in slope-intercept form and passes through the point (-4, 3)

Hello:
the equation is : y = ax+b
the slope is a : a×(-14) = -1( perpendicular to a line with a slope of -14)

because ;the slope of the line : y = −14x + 2

a = 1/14          y=(1/14)x+b
the line that passes through (-4, 3) : 3 = (1/14)(-4)+b
b = 46/4 
 the equation is :  y  = (1/14)x+46/4

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116