in the triangles, bc is congruent to rs and ac is congruent to tsif rt is greater than ba, which correctly compares angles c and s?

Angle S > Angle C

Step-by-step explanation:

Given that in the triangles,BC is congruent to RS and AC is congruent to TS.

If RT =BA we have the two triangles congruent by SSS axiom

Hence by cpct property the two angles C and S would be equal

But RT>BA

Hence angle opposite RT must be greater than angle opposite BA

i.e. Angle S>Angle C

The comparison of angles C and S gives that

Angle C is less than angle S