An alloy weighing 30 lbs. is 11% tin. the alloy was made by mixing a 15% tin alloy and a 9% tin alloy. how many pounds of each alloy were used to make the 11% alloy? lbs. of the 15% alloy and lbs. of the 9% alloy.

We let x = pounds of alloy that is 15% tin

The problem is modeled by the equation:

0.11(30) = 0.15x + 0.09(30-x)

The equation means that the amount of tin does not change. Also, the amount of alloy (total weight - weight of 15% alloy) is (30-x).  

Solving for x:

3.3 = 0.15x +2.7 - 0.09x

.06x = 0.6

x = 10 lbs

30-10 = 20 lbs

10 lbs. of the 15% alloy and 20 lbs. of the 9% alloy

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

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step-by-step explanation: